What is my tincture strength?

by Rob


We have been making Olive Leave Extract recently. Looks like it is good. We base it on 40% alcohol.
2 Questions:
- How fine do you cut the leaves? We cut it with a knife and scissors. Do you cut with a grinder?
- We do not know how much mg oleuropein is contained in 2,5 ml of the extract? Do you know roughly how much this contains?


You can cut the leaves very finely or shred them in a food processor with a little of the alcohol.
You want to draw as much out of the cells as possible so the finer the better.

I had the same question about strength from a previous visitor.
You need to know the dry weight of leaves used and the volume of alcohol.
In this case it was 4oz of leaves in 8oz of vodka.

Good quality dried leaves contain about 2-4% by weight of oleuropein.
Lets assume you got most of the oleuropein out of the leaves.

You have 4oz =113g of leaves. At 4% you will have about 113x0.04 = 4,52g oleuropein.
You use 8oz (226g or very roughly 226ml) of Vodka.

You have 4,52g x 1000 = 4520mg oleuropein in your whole bottle of tincture.
As you won't drink the leaves, and the oleuropein is dissolved, you have 4520g/226ml of tincture which equates to 20mg/ml.(which is quite a good strength).

This is obviously very rule-of-thumb, but there are other actives in the olive leaf so the overall effect should be about equivalent.

Comments for What is my tincture strength?

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What is the approximate oleuropein content of fresh olive leaves
by: Marina from New Zealand

firstly your site is absolutely fabulous! So much information! Thank you!
I have just made my second batch of olive leaf tincture using fresh leaves from my own sprayfree tree and wondered what its strength is approximately.
You say dried leaves contain 2-4% oleuropein by weight approximately. Any idea what it is for fresh leaves?
So I could calculate my tincture's strength.

Thank you!

Thank you for your comments Marina and I'm thrilled you have found the site helpful.

The answer would vary widely I imagine, but I found one source of information from a test recorded on Pubmed (PMID: 27447942) which you can access on the internet.

A short excerpt is shown below;

"Results: The major phenolic compound identified in the leaves was oleuropein, and the total content of phenolic compounds in this material reached 70 g kg-1 fresh weight".

So 70g/1000g = 7% phenolic compounds.
There is no mention of the proportion of oleuropein to the other phenolic compounds but if we take a stab at 50% then the oleuropein content would be 3.5% which is still in the ball park of 2-4%.
So a conservative estimate I would think is about 2% oleuropein for fresh leaves.

All the best,


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